If a straight line is equally inclined at an angle $ \theta $ with all the three coordinate axes, then $ \tan \theta =$
Step 1: Let the direction cosines of the line be \( \cos \theta \), which is the same for each axis since the line is equally inclined with all three axes.
Step 2: Using the fact that the sum of the squares of the direction cosines is equal to 1 for any line in three-dimensional space: \[ \cos^2 \theta + \cos^2 \theta + \cos^2 \theta = 1 \] This simplifies to: \[ 3 \cos^2 \theta = 1 \] \[ \cos^2 \theta = \frac{1}{3} \]
Step 3: Taking the square root of both sides: \[ \cos \theta = \frac{1}{\sqrt{3}} \]
Step 4: Now, we know that: \[ \tan \theta = \frac{1}{\cos \theta} = \sqrt{2} \] Thus, the value of \( \tan \theta \) is \( \sqrt{2} \).
Match the pollination types in List-I with their correct mechanisms in List-II:
List-I (Pollination Type) | List-II (Mechanism) |
---|---|
A) Xenogamy | I) Genetically different type of pollen grains |
B) Ophiophily | II) Pollination by snakes |
C) Chasmogamous | III) Exposed anthers and stigmas |
D) Cleistogamous | IV) Flowers do not open |