Question:
If A speaks truth with probability $\frac{4}{5}$ and B with $\frac{3}{4}$, find probability they contradict.
If A speaks truth with probability $\frac{4}{5}$ and B with $\frac{3}{4}$, find probability they contradict.
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Contradictions. Contradiction = exactly one speaks the truth; sum of two exclusive cases.
Updated On: May 17, 2025
- $\frac{3}{20}$
- $\frac{1}{5}$
- $\frac{7}{20}$
- $\frac{4}{5}$
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The Correct Option is C
Solution and Explanation
Contradiction = A true, B false OR A false, B true.
\[
P = \left(\frac{4}{5} \cdot \frac{1}{4}\right) + \left(\frac{1}{5} \cdot \frac{3}{4}\right) = \frac{1}{5} + \frac{3}{20} = \frac{7}{20}
\]
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