Question:

If a set \( A \) has \( n \) elements, then the number of functions defined from \( A \) to \( A \) that are not one-one is:

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Remember, total number of functions from a set with \( n \) elements to itself is \( n^n \), and number of one-one functions is \( n! \). Their difference gives the count of not one-one functions.
Updated On: May 15, 2025
  • \( n^{n^2} \)
  • \( n! - \left( {^nC_0} + {^nC_1} + {^nC_2} + \cdots + {^nC_n} \right) \)
  • \( n^n - n! \)
  • \( n^n \)
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The Correct Option is C

Solution and Explanation

The total number of functions from a set with \( n \) elements to itself is: \[ n^n \] The number of one-one (injective) functions from \( A \) to \( A \) is: \[ n! \] Therefore, the number of functions that are not one-one is: \[ n^n - n! \]
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