Question:
If \(A=\begin{pmatrix}1&1\\1&1 \end{pmatrix}\) and \(n\epsilon N\) then An is equal to
If \(A=\begin{pmatrix}1&1\\1&1 \end{pmatrix}\) and \(n\epsilon N\) then An is equal to
Updated On: Oct 4, 2024
- 2nA
- 2n-1A
- nA
- none of these
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The Correct Option is B
Solution and Explanation
The correct option is (B): 2n-1A
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