Question:

If a planet has twice the mass of earth and three times the radius (R)(R) of earth, then the escape velocity of the planet is (υe\upsilon_e = escape velocity of earth)

Updated On: Jun 7, 2022
  • 12υe\sqrt{ \frac{1}{2}} \upsilon_e
  • 23υe\sqrt{ \frac{2}{3}} \upsilon_e
  • 2υe\sqrt{2} \upsilon_e
  • none of these
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The Correct Option is B

Solution and Explanation

Escape velocity,υe=2gR\upsilon_e = \sqrt{2gR}
=2GMR2R = \sqrt{\frac{2GM}{R^2}} R (  g=GMR2)\left( \because \:\: g = \frac{GM}{R^2} \right)
  υeMR\therefore \:\: \upsilon_e \propto \sqrt{\frac{M}{R}} ...(i)
Given, Mp=2MM_p = 2M and Rp=3RR_p = 3R
   (υe)p=23υe\therefore \:\:\: (\upsilon_e)_p = \sqrt{\frac{2}{3}} \upsilon_e (Using (i))
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].