Step 1: An even prime number is a number that is both even and prime. The only even prime number is \( 2 \).
Step 2: Each die has the numbers \( 1, 2, 3, 4, 5, 6 \). For the condition to be satisfied (getting an even prime number on each die), both dice must show the number \( 2 \).
Step 3: The total number of possible outcomes when two dice are thrown is: \[ 6 \times 6 = 36. \]
Step 4: The only favorable outcome is when both dice show \( 2 \), so there is exactly one favorable outcome.
Step 5: Therefore, the probability of getting an even prime number on each die is: \[ \frac{1}{36}. \] Thus, the correct answer is \( \frac{1}{36} \).
Directions: In Question Numbers 19 and 20, a statement of Assertion (A) is followed by a statement of Reason (R).
Choose the correct option from the following:
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
(C) Assertion (A) is true, but Reason (R) is false.
(D) Assertion (A) is false, but Reason (R) is true.
In an experiment of throwing a die,
Assertion (A): Event $E_1$: getting a number less than 3 and Event $E_2$: getting a number greater than 3 are complementary events.
Reason (R): If two events $E$ and $F$ are complementary events, then $P(E) + P(F) = 1$.
If probability of happening of an event is 57%, then probability of non-happening of the event is
If the value of \( \cos \alpha \) is \( \frac{\sqrt{3}}{2} \), then \( A + A = I \), where \[ A = \begin{bmatrix} \sin\alpha & -\cos\alpha \\ \cos\alpha & \sin\alpha \end{bmatrix}. \]