Step 1: An even prime number is a number that is both even and prime. The only even prime number is \( 2 \).
Step 2: Each die has the numbers \( 1, 2, 3, 4, 5, 6 \). For the condition to be satisfied (getting an even prime number on each die), both dice must show the number \( 2 \).
Step 3: The total number of possible outcomes when two dice are thrown is: \[ 6 \times 6 = 36. \]
Step 4: The only favorable outcome is when both dice show \( 2 \), so there is exactly one favorable outcome.
Step 5: Therefore, the probability of getting an even prime number on each die is: \[ \frac{1}{36}. \] Thus, the correct answer is \( \frac{1}{36} \).
If the value of \( \cos \alpha \) is \( \frac{\sqrt{3}}{2} \), then \( A + A = I \), where \[ A = \begin{bmatrix} \sin\alpha & -\cos\alpha \\ \cos\alpha & \sin\alpha \end{bmatrix}. \]