Let $ A = \begin{bmatrix} 2 & 2 + p & 2 + p + q \\4 & 6 + 2p & 8 + 3p + 2q \\6 & 12 + 3p & 20 + 6p + 3q \end{bmatrix} $ If $ \text{det}(\text{adj}(\text{adj}(3A))) = 2^m \cdot 3^n, \, m, n \in \mathbb{N}, $ then $ m + n $ is equal to:

Comparative Financial Data as on 31st March, 2024 and 2023
| Particulars | 31.03.2024 (₹) | 31.03.2023 (₹) |
|---|---|---|
| Surplus (P&L) | 17,00,000 | 8,00,000 |
| Patents | -- | 50,000 |
| Sundry Debtors | 5,80,000 | 4,20,000 |
| Sundry Creditors | 1,40,000 | 60,000 |
| Cash and Cash Equivalents | 2,00,000 | 90,000 |