Question:

If A is a square matrix of order 4 and |A| = 4, then |2A| will be:

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When working with the determinant of a scalar multiple of a matrix, the key idea is that multiplying a matrix \(A\) by a scalar \(k\) results in the determinant being multiplied by \(k^n\), where \(n\) is the size of the matrix. This property helps simplify the calculation of determinants when the matrix is scaled by a constant. For a \(4 \times 4\) matrix, raising the scalar to the power of 4 is crucial for finding the correct result.

Updated On: Apr 10, 2025
  • 8
  • 64
  • 16
  • 4
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The Correct Option is B

Approach Solution - 1

For an $n×n$ matrix, $|kA|$= $k^n$ ·|A|.
Here, $|2A|$ = 24·\(\times\)4 = 64
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Approach Solution -2

For an \(n \times n\) matrix, the determinant of a scalar multiple of the matrix is given by:

\[ |kA| = k^n \cdot |A| \]

Here, we are given that \(A\) is a \(4 \times 4\) matrix and we are asked to find \( |2A| \). Applying the formula:

\[ |2A| = 2^4 \cdot |A| \]

The determinant of \(2A\) is then:

\[ |2A| = 2^4 \cdot 4 = 16 \cdot 4 = 64 \]

Conclusion: Thus, \( |2A| = 64 \).

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