If a full wave rectifier circuit is operating from 50 Hz mains, the fundamental frequency in the ripple will be:
- 25 Hz
- 50 Hz
- 70.7 Hz
- 100 Hz
The Correct Option is D
Solution and Explanation
A full-wave rectifier circuit operating from a 50 Hz mains will produce a ripple frequency that is twice the frequency of the mains supply. This is because a full-wave rectifier rectifies both halves of the AC cycle, effectively doubling the frequency of the ripples.
Therefore,
Fundamental frequency = 2 x Mains frequency
Fundamental frequency = 2 x 50 Hz = 100 Hz
So, the correct option is (D): 100 Hz
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Concepts Used:
Applications of diode
Diodes are used in many applications. By removing the signal component, several of them convert AC current to DC current also are known as rectifiers when used in this position. Diodes act as electric switches and can block voltage spikes, making them ideal for surgical protectors. They are hired to do digital logic. Some things are made from diodes such as power supply and voltage doubles. The sensors, as well as light on lighting devices and lasers, depend on LEDs. For electronic tuning, varactors are used, and for compressing transients in AC lines varistors are used. Zener diodes are used as voltage regulators where varactors are used for electronic tuning, and varistors are used for compressing transients in AC lines.
On the base of diodes, transistors and op-amps are built. The most common diode mode is the p-n junction. One (n) object with electrons as the charging conductor closes the second object (p) with holes (well-charged particles acted as depleted areas of electrons) as the charge carriers on this type of diode. Where they connect, the narrowing space forms, where electrons are dispersed to fill holes in the p-side. This effectively stops the flow of electrons. When a positive voltage is given to the p-side of this junction, electrons may easily move from it and the current flows into the diode to fill the holes. The shrinkage area expands as the negative bias interacts (i.e., negative voltage is given to the p-side), making the electrons harder to move across.