If the discrete random variable \(X\) follows a uniform distribution and assumes the values 8, 9, 11, 15, 18, and 20, then we need to calculate \(P(|X - 14| < 5)\). This problem can be solved as follows:
First, express the inequality \(|X - 14| < 5\):
\(-5 < X - 14 < 5\)
By adding 14 to all parts of the inequality, we obtain:
\(9 < X < 19\)
Thus, we are looking for values of \(X\) within the range from 10 to 18 inclusive (since \(X\) can only assume integer values).
The values of \(X\) that satisfy this are 11, 15, and 18.
Next, determine how many values satisfy this condition. There are 3 values: 11, 15, and 18.
Calculate the probability:
The uniform distribution over 6 values (8, 9, 11, 15, 18, and 20) means each has a probability of \(\frac{1}{6}\).
Thus, the probability \(P(|X - 14| < 5)\) is given by:
\[P(X = 11) + P(X = 15) + P(X = 18) = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}\]
Therefore, \(P(|X - 14| < 5)\) is \(\frac{1}{2}\).
Three distinct numbers are selected randomly from the set \( \{1, 2, 3, \dots, 40\} \). If the probability, that the selected numbers are in an increasing G.P. is \( \frac{m}{n} \), where \( \gcd(m, n) = 1 \), then \( m + n \) is equal to:
A board has 16 squares as shown in the figure. Out of these 16 squares, two squares are chosen at random. The probability that they have no side in common is:
Here are two analogous groups, Group-I and Group-II, that list words in their decreasing order of intensity. Identify the missing word in Group-II.
Abuse \( \rightarrow \) Insult \( \rightarrow \) Ridicule
__________ \( \rightarrow \) Praise \( \rightarrow \) Appreciate
The 12 musical notes are given as \( C, C^\#, D, D^\#, E, F, F^\#, G, G^\#, A, A^\#, B \). Frequency of each note is \( \sqrt[12]{2} \) times the frequency of the previous note. If the frequency of the note C is 130.8 Hz, then the ratio of frequencies of notes F# and C is: