Question:

If a compound has octahedral geometry, what is the central atom’s hybridization?

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In octahedral geometry, the hybridization of the central atom is \( sp^3d^2 \), using six orbitals.
  • sp\(^2\)
  • dsp\(^2\)
  • sp\(^3\)d\(^2\)
  • sp\(^3\)d\(^3\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding octahedral geometry.
In an octahedral geometry, there are six bonding regions around the central atom. This requires the central atom to have six hybridized orbitals, which is achieved by using the \( sp^3d^2 \) hybridization.
Step 2: Conclusion.
The central atom in an octahedral compound undergoes \( sp^3d^2 \) hybridization, which corresponds to option (C).
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