Step 1: Understanding the genetic inheritance of colour blindness.
Colour blindness is an X-linked recessive trait. In a colour-blind woman, the genotype is X\(^c\)X\(^c\), where X\(^c\) represents the X chromosome carrying the colour-blind allele. The man, being normal, will have the genotype X\(^N\)Y, where X\(^N\) represents the normal X chromosome and Y is the male sex chromosome.
Step 2: Genetic inheritance for a son.
Sons inherit their X chromosome from their mother and their Y chromosome from their father. Since the mother is colour-blind (X\(^c\)X\(^c\)), she can only pass on the X\(^c\) chromosome. The father, being normal, will pass on the Y chromosome. Thus, the son will inherit X\(^c\)Y, making him colour-blind.
Step 3: Conclusion.
Since the son will always inherit the X\(^c\) chromosome from his colour-blind mother, he will be colour-blind. Therefore, the chance that their boy child will be colour-blind is 100%. The correct answer is 100.
If a heterozygous tall plant (Tt) is crossed with a dwarf plant (tt), what will be the phenotypic ratio of the offspring?
The vector, shown in the figure, has promoter and RBS sequences in the 300 bp region between the restriction sites for enzymes X and Y. There are no other sites for X and Y in the vector. The promoter is directed towards the Y site. The insert containing only an ORF provides 3 fragments after digestion with both enzymes X and Y. The ORF is cloned in the correct orientation in the vector using the single restriction enzyme Y. The size of the largest fragment of the recombinant plasmid expressing the ORF upon digestion with enzyme X is ........... bp. (answer in integer) 