When a charged particle enters a magnetic field, the motion of the particle is influenced by the Lorentz force, which is given by:
\[ F = q(\mathbf{v} \times \mathbf{B}) \]
Where:
The force \( F \) is perpendicular to the velocity \( \mathbf{v} \), so the particle will follow a circular path due to the magnetic force. However, when the velocity \( \mathbf{v} \) has a component along the magnetic field \( \mathbf{B} \), this component of the velocity does not experience any magnetic force because the magnetic force is perpendicular to both the velocity and the magnetic field.
Thus, the particle will:
The combination of these two motions results in a helical path.
Therefore, the correct answer is:
\[ \boxed{\text{D) A helical path}} \]
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: