Question:
If a car at rest accelerates uniformly to a speed of 144 km/hour in 20 second it covers a distance of
If a car at rest accelerates uniformly to a speed of 144 km/hour in 20 second it covers a distance of
Updated On: Aug 20, 2024
- 400 m
- 1440 m
- 2880m
- 25m
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The Correct Option is A
Solution and Explanation
u = 0, v = 144 km/hour $ = 144 \times \frac{5}{18} m/ \sec$
$ = 40 / m / \sec$
$v = u + at$
$\Rightarrow \, a = \frac{v - u}{t} = \frac{40 - 0 }{20} = 2 m / \sec^2$
$\therefore \, s = ut + \frac{1}{2} at^2$
$ = \frac{1}{2} \times 2 \times (20)^2 = 400 m $
$ = 40 / m / \sec$
$v = u + at$
$\Rightarrow \, a = \frac{v - u}{t} = \frac{40 - 0 }{20} = 2 m / \sec^2$
$\therefore \, s = ut + \frac{1}{2} at^2$
$ = \frac{1}{2} \times 2 \times (20)^2 = 400 m $
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.