Question:

If \(|\vec{a}\times\vec{b}|\) + \(|\vec{a}.\vec{b}|^2=36\) and \(|\vec{a}|=3\) then \(|\vec{b}|\) is equal to

Updated On: Apr 20, 2024
  • 9
  • 4
  • 36
  • 2
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The Correct Option is A

Solution and Explanation

The correct answer is (A) : 9.
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