Given:
\( A \) and \( B \) are matrices of order 3.
\( |A| = 5 \), \( |B| = 3 \).
We are asked to find \( |3ABI| \).
According to the properties of determinants, we know: \[ |kA| = k^n |A| \] where \( k \) is a scalar and \( n \) is the order of the matrix.
Since \( A \) and \( B \) are 3x3 matrices, \( n = 3 \). Therefore:
\[ |3A| = 3^3 |A| = 27 \times 5 = 135 \] We also know that \( |ABI| = |A| \times |B| \times |I| \), where \( |I| = 1 \). So: \[ |ABI| = |A| \times |B| = 5 \times 3 = 15 \] Now, we need to calculate \( |3ABI| \). We know: \[ |3ABI| = |3A| \times |B| \times |I| = 135 \times 3 = 405 \]
Thus, the correct answer is (B): 405.