Given the set \(A = \{a, b, c\}\), we need to find the number of binary operations on A.
A binary operation on A is a function from \(A \times A\) to A.
The number of elements in A is |A| = 3.
The number of elements in \(A \times A\) is \(|A \times A| = |A| \times |A| = 3 \times 3 = 9\).
For each of the 9 elements in \(A \times A\), the binary operation can map it to any of the 3 elements in A.
Therefore, the total number of binary operations is \(3^{|A \times A|} = 3^9\).
Thus, the correct option is (D) \(3^9\).
For a set \( A = \{a, b, c\} \), the number of binary operations on \( A \) is calculated as follows:
1. A binary operation takes two elements from the set and maps them to one element in the set.
2. For each pair of elements from \( A \), there are 3 possible outcomes, since \( A \) has 3 elements. Since there are 3 elements in \( A \), the total number of ordered pairs of elements is \( 3 \times 3 = 9 \).
3. For each of these 9 pairs, there are 3 choices for the result.
Therefore, the total number of binary operations is: \[ 3^9 \] Answer: (D) \( 3^9 \).
The mean of coefficients of x, x2, ....., x7 in the binomial expansion of (2 + x)9 is?
The number of rational terms in the expansion of (33/4 + 53/2)60?
In an experiment to determine the figure of merit of a galvanometer by half deflection method, a student constructed the following circuit. He applied a resistance of \( 520 \, \Omega \) in \( R \). When \( K_1 \) is closed and \( K_2 \) is open, the deflection observed in the galvanometer is 20 div. When \( K_1 \) is also closed and a resistance of \( 90 \, \Omega \) is removed in \( S \), the deflection becomes 13 div. The resistance of galvanometer is nearly:
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is