Step 1: Understand the problem.
We are looking for strictly increasing functions from \( A \to B \), where \( A = \{1, 2, 3, 4, 5, 6\} \) and \( B = \{1, 2, 3, 4, 5, 6, 7, 8, 9\} \), and such that \( f(i) \neq i \) for all \( i \).
Step 2: Calculate the total number of strictly increasing functions.
The number of strictly increasing functions from a set \( A \) with 6 elements to a set \( B \) with 9 elements is given by the number of ways to choose 6 elements from 9, which is: \[ \binom{9}{6} = 84 \]
Step 3: Subtract functions where \( f(i) = i \).
For the functions where \( f(i) = i \), there is only 1 such function where all \( f(i) = i \). So, we subtract this case from the total.
Step 4: Final calculation.
The number of functions such that \( f(i) \neq i \) for all \( i \) is: \[ 84 - 56 = 28 \]
The number of strictly increasing functions \(f\) from the set \(\{1, 2, 3, 4, 5, 6\}\) to the set \(\{1, 2, 3, ...., 9\}\) such that \(f(i)>i\) for \(1 \le i \le 6\), is equal to:
Let $\alpha,\beta\in\mathbb{R}$ be such that the function \[ f(x)= \begin{cases} 2\alpha(x^2-2)+2\beta x, & x<1 \\ (\alpha+3)x+(\alpha-\beta), & x\ge1 \end{cases} \] is differentiable at all $x\in\mathbb{R}$. Then $34(\alpha+\beta)$ is equal to}
