Question:

If $8\sqrt{x}\left(\sqrt{9+\sqrt{x}}\right)dy = \left(\sqrt{4+\sqrt{9+\sqrt{x}}}\right)^{-1}\,\,dx, \,\,\,\,x > 0$ and $

Updated On: Jun 14, 2022
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The Correct Option is A

Solution and Explanation

$dy =\left(\frac{1}{8 \sqrt{ x }(\sqrt{9+\sqrt{ x }})(\sqrt{4+\sqrt{9+\sqrt{ x }}})}\right) dx$
Let $4+\sqrt{9+\sqrt{x}}=t$
$\Rightarrow \frac{1}{2 \sqrt{9+\sqrt{x}}} \cdot \frac{1}{2 \sqrt{x}} d x=d t $
$\Rightarrow d y=\frac{d t}{2 \sqrt{t}}$
$\Rightarrow 2 d y=\frac{1}{\sqrt{t}} d t$
$2 y=2 \sqrt{t}+c$
$\Rightarrow 2 y=2 \sqrt{4+\sqrt{9+\sqrt{x}}}+c$
$y(0)=\sqrt{7} $
$\Rightarrow c=0 $
$y=\sqrt{4+\sqrt{9+\sqrt{x}}}$
$y(256)=3$
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Concepts Used:

Differential Equations

A differential equation is an equation that contains one or more functions with its derivatives. The derivatives of the function define the rate of change of a function at a point. It is mainly used in fields such as physics, engineering, biology and so on.

Orders of a Differential Equation

First Order Differential Equation

The first-order differential equation has a degree equal to 1. All the linear equations in the form of derivatives are in the first order. It has only the first derivative such as dy/dx, where x and y are the two variables and is represented as: dy/dx = f(x, y) = y’

Second-Order Differential Equation

The equation which includes second-order derivative is the second-order differential equation. It is represented as; d/dx(dy/dx) = d2y/dx2 = f”(x) = y”.

Types of Differential Equations

Differential equations can be divided into several types namely

  • Ordinary Differential Equations
  • Partial Differential Equations
  • Linear Differential Equations
  • Nonlinear differential equations
  • Homogeneous Differential Equations
  • Nonhomogeneous Differential Equations