First, express both sides of the equation in terms of powers of 2:
\[
8 = 2^3 \quad \text{and} \quad 16 = 2^(4)
\]
Thus, the equation becomes:
\[
(2^3)^{2x - 4} = (2^4)^{x - 2}.
\]
Simplifying:
\[
2^{3(2x - 4)} = 2^{4(x - 2)} \quad \Rightarrow \quad 2^{6x - 12} = 2^{4x - 8}.
\]
Since the bases are the same, equate the exponents:
\[
6x - 12 = 4x - 8 \quad \Rightarrow \quad 2x = 4 \quad \Rightarrow \quad x = (2)
\]