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if 5 4x 2 1 3x 4x 8 and x 0 then what is the value
Question:
If
\(\frac{5(4x^2+1)-3x}{4x}=8\)
and x ≠ 0, then what is the value of
\((√2x-\frac{1}{√2x}) \)
?
CAT
Updated On:
Nov 17, 2025
\(\sqrt{(\frac{3}{2})}\)
\(\sqrt{(\frac{5}{2})}\)
\(\sqrt{(\frac{5}{4})}\)
\(\sqrt{(\frac{3}{4})}\)
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The Correct Option is
A
Solution and Explanation
The correct option is (A):
\(\sqrt{(\frac{3}{2})}\)
.
\(\frac{5(4x^2+1)-3x}{4x}=8\)
20x
2
+ 5 - 3x = 32x
20x
2
+ 5 = 35x
4x
2
- 7x + 1 = 0
4x
2
+ 1 = 7x... (i)
\(Now, (\sqrt2x-\frac{1}{\sqrt2x})=2x-2+\frac{1}{2x}\)
=
\(\frac{ (4x2- 4x + 1)}{2x}\)
=
\(\frac{(7x - 4x)}{2x}\)
(from (i))
Therefore,
\((\sqrt2x-\frac{1}{\sqrt2x})=\sqrt\frac{3}{2}\)
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