Question:

If 4(4b-3a) = 2(2b+c) = 8(c-a) and a + b + c = 11, then find the value of \(4(\frac{1}{ab}+\frac{1}{bc}+\frac{1}{ca})\)

Updated On: Sep 10, 2024
  • \(\frac{11}{9}\)
  • \(\frac{9}{11}\)
  • \(\frac{6}{5}\)
  • \(\frac{5}{6}\)
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The Correct Option is A

Solution and Explanation

The correct option is (A): \(\frac{11}{9}\)
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