Question

If \(3x^2-2ax+(a^2+2b^2+2c^2) = 2(ab+bc),\) then a,b,c can be in

• A. A.P
• B. G.P
• C. H.P
• D. none of these

Answer 1

The Correct Option is A

The given result can be expressed as follows :
\(\left\{x-(a-b)^2\right\}+\left\{x-(b-c)^2\right\}+(x-c)^2=0\)
\(x=a-b,x=b-c,x=c\)
\(a-b=b-c=c\)
From \(a-b=b-c,\ 2b=a+c\)
Therefore, \(a,b,c\) can be in A.P.
So, the correct option is (A) : A.P.