Question:
If=\(\frac{2x^2+x-6}{(x+2)^2-(x-2)^2}\), Q=\(\frac{x^2+3x+9}{(2x-3)(x^2-4)}\) and \(R=\frac{x^2-27}{x^4-4}\), then find the value of PXQ÷R
If=\(\frac{2x^2+x-6}{(x+2)^2-(x-2)^2}\), Q=\(\frac{x^2+3x+9}{(2x-3)(x^2-4)}\) and \(R=\frac{x^2-27}{x^4-4}\), then find the value of PXQ÷R
Updated On: Sep 13, 2024
- \(\frac{(x + 2)}{[2 (x - 3)]}\)
- \(\frac{(x + 2)}{(x - 3)}\)
- 2\(\frac{(x + 2)}{(x - 3)}\)
- 4\(\frac{(x + 2)}{(x - 3)}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{(x+2)^2}{[2(x-3)]}\)
\(P \times Q÷R\)=\(\frac{2x^2+x-6}{(x+2)^2+(x-2)^2}\times\frac{x^2+3x+9}{(2x-3)(x^2-4)}\times\frac{x^3-27}{x^4-16}\)
After simplifying :
\(\frac{x+2}{2(x^2+4}\times\frac{(x^2+4)}{(x-3)}\)
\(\frac{(x+2)}{2(x-3)}\).
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