Question:

If \(\tan \theta + \cot \theta = 2\), then \(\tan^2 \theta + \cot^2 \theta =\)

Updated On: Apr 5, 2025
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The Correct Option is B

Solution and Explanation

Correct answer:

Explanation:
Given: \[ \tan \theta + \cot \theta = 2 \] We need to find \( \tan^2 \theta + \cot^2 \theta \). Using the identity: \[ (\tan \theta + \cot \theta)^2 = \tan^2 \theta + \cot^2 \theta + 2 \] Substituting \( \tan \theta + \cot \theta = 2 \): \[ 2^2 = \tan^2 \theta + \cot^2 \theta + 2 \] \[ 4 = \tan^2 \theta + \cot^2 \theta + 2 \] \[ \tan^2 \theta + \cot^2 \theta = 4 - 2 = 2 \]

Hence, \( \tan^2 \theta + \cot^2 \theta = {2} \).

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