Question

If \( 156 = 2^x \times 3^y \times 13^z \), then \( x + y + z = \)?

• A. \( 4 \)
• B. \( 5 \)
• C. \( 3 \)
• D. \( 6 \)

Hint:

Break numbers into prime factors to solve exponent equations.

Answer 1

The Correct Option is B

Prime factorizing 156:
\[ 156 = 2^2 \times 3^1 \times 13^1. \] \[ x = 2, \quad y = 1, \quad z = 1. \] \[ x + y + z = 2 + 1 + 1 = 5. \]