Step 1: Understanding the proportion.
The given proportion is \( 15 : 225 :: 35 : x \). From this, we can use cross multiplication to find \( x \).
\[
\frac{15}{225} = \frac{35}{x}
\]
\[
x = \frac{35 \times 225}{15} = 525.
\]
Step 2: Solving for \( \sqrt{x + 100} \).
Now, we need to calculate \( \sqrt{x + 100} \) where \( x = 525 \).
\[
\sqrt{525 + 100} = \sqrt{625} = 25.
\]
Step 3: Conclusion.
The correct answer is (B) 20.
A weight of $500\,$N is held on a smooth plane inclined at $30^\circ$ to the horizontal by a force $P$ acting at $30^\circ$ to the inclined plane as shown. Then the value of force $P$ is:
A steel wire of $20$ mm diameter is bent into a circular shape of $10$ m radius. If modulus of elasticity of wire is $2\times10^{5}\ \text{N/mm}^2$, then the maximum bending stress induced in wire is: