The power consumed by a bulb is given by the formula:
\[
P = \frac{V^2}{R}
\]
Where:
- \( V \) is the voltage across the bulb,
- \( R \) is the resistance of the bulb.
First, calculate the resistance of the bulb using the rated values:
\[
R = \frac{250^2}{100} = \frac{62500}{100} = 625 \, \Omega
\]
Now, apply the reduced voltage (125V) and calculate the power:
\[
P = \frac{V^2}{R} = \frac{125^2}{625} = \frac{15625}{625} = 25 \, \text{W}
\]
Thus, the power consumed by the bulb when 125V is applied is 25 W, which is option (1).