Step 1: Understanding the Liberation of Hydrogen Gas in the Given Reactions
- Reaction 1: \( Al + HCl \)
- Aluminium reacts with hydrochloric acid to form aluminium chloride and liberates hydrogen gas: \[ 2Al + 6HCl \rightarrow 2AlCl_3 + 3H_2 \]
- Hydrogen gas is liberated.
- Reaction 2: \( NaBH_4 + I_2 \)
- Sodium borohydride reacts with iodine to form hydrogen gas: \[ NaBH_4 + 2I_2 \rightarrow BI_3 + NaI + 2H_2 \]
- Hydrogen gas is liberated.
- Reaction 3: \( BF_3 + LiAlH_4 \)
- Lithium aluminium hydride (\( LiAlH_4 \)) is used as a reducing agent.
- No hydrogen gas is released in this reaction.
- Reaction 4: \( Al + NaOH \)
- Aluminium reacts with sodium hydroxide in water to form sodium aluminate and liberates hydrogen gas: \[ 2Al + 2NaOH + 6H_2O \rightarrow 2Na[Al(OH)_4] + 3H_2 \]
- Hydrogen gas is liberated.
Step 2: Identifying the Correct Answer
- The only reaction where hydrogen gas is NOT liberated is \( BF_3 + LiAlH_4 \).
- Option (3) is correct.
A laser beam has intensity of $4.0\times10^{14}\ \text{W/m}^2$. The amplitude of magnetic field associated with the beam is ______ T. (Take $\varepsilon_0=8.85\times10^{-12}\ \text{C}^2/\text{N m}^2$ and $c=3\times10^8\ \text{m/s}$)