The reaction is acidic cleavage of an ether using concentrated HBr and heat:
\[
\text{C}_6\text{H}_5\text{–O–CH(CH}_3)_2 \xrightarrow{\text{HBr},\ \Delta} \text{C}_6\text{H}_5\text{OH} + \text{(CH}_3)_2\text{CHBr}
\]
Mechanism:
- Protonation of ether oxygen
- Cleavage at the alkyl side (not the aromatic side)
- Phenol remains intact, and the alkyl group becomes an alkyl halide