Question:

Identify the product formed in the given reaction. 

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When reducing nitro compounds with Sn/HCl, the nitro group is typically reduced to an amine group. This is an important reaction in organic chemistry for the synthesis of aromatic amines.
Updated On: Apr 18, 2025
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The Correct Option is B

Solution and Explanation

This is a typical reduction and substitution reaction. Let's break it down step by step:

Step 1: Reduction with Sn/HCl

The nitro group (NO2) on the benzene ring undergoes a reduction reaction in the presence of tin (Sn) and hydrochloric acid (HCl).

In this reduction process, the nitro group (-NO2) is converted into an amine group (-NH2).

Key Reaction: NO2 + 3H2 → NH2 + 2H2O

This results in the formation of an amine group (-NH2) on the benzene ring, which is the key transformation in this reaction.

Step 2: Reaction with CHCl3 and NaOH

The second part of the reaction involves the use of chloral (CHCl3) and aqueous sodium hydroxide (NaOH).

Typically, this combination can lead to a substitution reaction, but in this case, the primary focus is on the reduction of the nitro group to the amine group, which has already been achieved in Step 1.

Therefore, the second step does not significantly alter the product obtained from the first step.

Final Product

After both steps, the final product has an amine group (-NH2) attached to the benzene ring. This makes the correct product B.

In conclusion: The reaction primarily results in the conversion of the nitro group (-NO2) to the amine group (-NH2), making the final product B.

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