Question:

Identify the pairs in which both molecules do not possess same type of hybridization:
I. H$_2$O, SO$_2$
II. PCl$_3$, NH$_3$
III. SO$_2$, SO$_3$
IV. BCl$_3$, NCl$_3$

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Check hybridization using: steric number = bonded atoms + lone pairs. sp$^3$ → tetrahedral, sp$^2$ → trigonal planar. sp → linear.
Updated On: Oct 27, 2025
  • I, III only
  • II, IV only
  • II, III only
  • I, IV only
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The Correct Option is D

Solution and Explanation

• H$_2$O: sp$^3$, SO$_2$: sp$^2$ → different hybridization.
• BCl$_3$: sp$^2$, NCl$_3$: sp$^3$ → different hybridization.
• Other pairs have same hybridization.
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