Identify the final product formed when Toluene undergoes a series of reactions with reagents given in the order:
(i) \( \text{Cl}_2 / \text{Sunlight} \)
(ii) \( \text{H}_2\text{O}/373 \, \text{K} \)
(iii) Acetophenone / \( \text{OH}^- \) at 293 K
The given reactions are:
1. Reaction with \( \text{Cl}_2 \) / Sunlight: Toluene (\( \text{C}_6\text{H}_5\text{CH}_3 \)) undergoes a free radical substitution reaction with chlorine in the presence of sunlight. This results in the formation of chlorotoluene (where a hydrogen atom is replaced by chlorine in the methyl group, forming a benzyl chloride). The methyl group (\( \text{CH}_3 \)) gets chlorinated to form a benzyl chloride intermediate (\( \text{C}_6\text{H}_4\text{CH}_2\text{Cl} \)).
2. Reaction with \( \text{H}_2\text{O}/373K \): In this step, the benzyl chloride undergoes a hydrolysis reaction, resulting in the formation of the corresponding alcohol. The benzyl chloride is converted to a benzyl alcohol.
3. Reaction with Acetophenone / \( \text{OH}^- \) at 293 K: In the final step, the product reacts with acetophenone in the presence of a base (\( \text{OH}^- \)) at 293 K. This leads to the formation of a conjugated enone structure, where the product is 1, 3-Diphenylprop-2-en-1-one.
Thus, the final product is 1, 3-Diphenylprop-2-en-1-one. Hence, the correct answer is \( (A) \).
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |
Identify the products C, D, and F formed in the following sets of reactions.
Which one of the following is the correct order of reagents to be used to convert [A] to [X]?
If the ratio of lengths, radii and Young's Moduli of steel and brass wires in the figure are $ a $, $ b $, and $ c $ respectively, then the corresponding ratio of increase in their lengths would be: