Identify the final product formed when Toluene undergoes a series of reactions with reagents given in the order:
(i) \( \text{Cl}_2 / \text{Sunlight} \)
(ii) \( \text{H}_2\text{O}/373 \, \text{K} \)
(iii) Acetophenone / \( \text{OH}^- \) at 293 K
The given reactions are:
1. Reaction with \( \text{Cl}_2 \) / Sunlight: Toluene (\( \text{C}_6\text{H}_5\text{CH}_3 \)) undergoes a free radical substitution reaction with chlorine in the presence of sunlight. This results in the formation of chlorotoluene (where a hydrogen atom is replaced by chlorine in the methyl group, forming a benzyl chloride). The methyl group (\( \text{CH}_3 \)) gets chlorinated to form a benzyl chloride intermediate (\( \text{C}_6\text{H}_4\text{CH}_2\text{Cl} \)).
2. Reaction with \( \text{H}_2\text{O}/373K \): In this step, the benzyl chloride undergoes a hydrolysis reaction, resulting in the formation of the corresponding alcohol. The benzyl chloride is converted to a benzyl alcohol.
3. Reaction with Acetophenone / \( \text{OH}^- \) at 293 K: In the final step, the product reacts with acetophenone in the presence of a base (\( \text{OH}^- \)) at 293 K. This leads to the formation of a conjugated enone structure, where the product is 1, 3-Diphenylprop-2-en-1-one.
Thus, the final product is 1, 3-Diphenylprop-2-en-1-one. Hence, the correct answer is \( (A) \).


200 ml of an aqueous solution contains 3.6 g of Glucose and 1.2 g of Urea maintained at a temperature equal to 27$^{\circ}$C. What is the Osmotic pressure of the solution in atmosphere units?
Given Data R = 0.082 L atm K$^{-1}$ mol$^{-1}$
Molecular Formula: Glucose = C$_6$H$_{12}$O$_6$, Urea = NH$_2$CONH$_2$