Question

Identify the end-product $ [D] $ formed when solution salicylate undergoes the following series of reactions.

• A.
• B.
• C.
• D.

Hint:

When solving problems involving organic reactions, carefully track the functional groups and intermediates. Key reactions such as elimination, nucleophilic substitution, or addition will guide you to the correct product.

Answer 1

The Correct Option is D

The reaction in question involves the transformation of salicylate under a given series of reactions that ultimately leads to the formation of the end-product. Here's the breakdown: -
Step 1: The starting molecule is salicylate. When salicylate undergoes reactions involving an alkene (C=C) and possibly a base, it may lead to a dehydrohalogenation or elimination reaction.
-
Step 2: The sodium ion (Na) reacts with the phenol group, leading to the formation of sodium phenoxide (indicated by the Na attached to the oxygen).
-
Step 3: The compound undergoes a Michael addition or alkylation with an alkene like styrene (C6H5-CH=CH2). This results in the final product: an ethyl group (CH2-CH) attached to the aromatic ring.
Thus, the final product [D] is the sodium phenoxide with the ethyl group attached at the para position on the ring. Thus, the correct structure and compound is \( \text{CH}_2\text{CH}-\text{O-Na} \), which is option (D).