Question:

Identify the correct statement about the oxidation states of group 14 elements

Updated On: Mar 11, 2025
  • Carbon and Silicon mostly exhibit +4 oxidation state

  • Tin in +2 oxidation state is a reducing agent

  • Lead in +2 oxidation state is a reducing agent

  • The order of stability of +2 oxidation state follow the sequence Ge<Sn<Pb

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The Correct Option is C

Solution and Explanation

The correct option is: (C): Lead in +2 oxidation state is a reducing agent.

The member of group 14 possesses a set of 4 valence electrons, leading to an inherent oxidation state of +4. Nevertheless, due to the inert pair phenomenon, the lower oxidation state gains stability while the higher oxidation state loses stability. Consequently, this group showcases oxidation states of both +4 and +2.

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Concepts Used:

Group 14 Elements

The group 14 elements are also known as the carbon group. Sometimes it is also called crystallogens. The group 14 elements can be found on the right side of the periodic table. The elements of the carbon group are: 

  • Carbon - C
  • Silicon - Si
  • Germanium - Ge
  • Tin - Sn
  • Lead - Pb
  • Flerovium - FI

The group 14 elements or the carbon family belongs to the p-block of the periodic table. The carbon group is also the second group in the p-block.

Electronic Configuration:

The arrangement of electrons in the orbitals of a molecule or atom is known as electronic configuration. The general electronic configuration of the group 14 elements is ns2np2.

All group 14 elements have 4 electrons in the outer shell. Hence, the valency of the carbon family or group 14 elements is 4.

Properties of Group 14 Elements:

  • Covalent Radii
  • Ionization Enthalpy
  • Electronegativity
  • Metallic Character
  • Density
  • Four Covalent Compounds
  • The Melting and Boiling Points