Step 1: Deenbandhu Newspaper
‘Deenbandhu’ was a Marathi-language newspaper, and its editor was Krishnarao Arjun Keluskar, not Krishnarao Bholekar. Krishnarao Arjun Keluskar was a noted journalist and editor in the 19th century who played a significant role in the social reform movements in Maharashtra.
Step 2: The Editor Confusion
Krishnarao Bholekar, another important figure in Marathi literature, was not the editor of ‘Deenbandhu.’ Instead, he was associated with other contributions to Marathi literature and journalism, making the mix-up understandable but incorrect in this context.
Read the following passage and answer the questions based on it :
Major Dhyan Chand, an expert player of hockey was also the captain of the Indian hockey team. Indian hockey team won a gold medal in 1936 at Berlin Olympics under his captaincy. He was also part of the previous Indian hockey teams in 1928 and 1932, which played at Olympics and won gold medals. 29th August, the birth date of Dhyan Chand is celebrated as National Sports Day in India. He was known as the ‘Wizard of Hockey’. He was honoured with a ‘Padmabhushan’ in 1956.
Complete the following chart :
Complete the following activity to prove that the sum of squares of diagonals of a rhombus is equal to the sum of the squares of the sides.
Given: PQRS is a rhombus. Diagonals PR and SQ intersect each other at point T.
To prove: PS\(^2\) + SR\(^2\) + QR\(^2\) + PQ\(^2\) = PR\(^2\) + QS\(^2\)
Activity: Diagonals of a rhombus bisect each other.
In \(\triangle\)PQS, PT is the median and in \(\triangle\)QRS, RT is the median.
\(\therefore\) by Apollonius theorem,
\[\begin{aligned} PQ^2 + PS^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(I)} \\ QR^2 + SR^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(II)} \\ \text{Adding (I) and (II),} \quad PQ^2 + PS^2 + QR^2 + SR^2 &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \\ &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \quad (\text{RT = PT}) \\ &= 4PT^2 + 4QT^2 \\ &= (\boxed{\phantom{X}})^2 + (2QT)^2 \\ \therefore \quad PQ^2 + PS^2 + QR^2 + SR^2 &= PR^2 + \boxed{\phantom{X}} \\ \end{aligned}\]