Question

Identify the correct output signal \( Y \) in the given combination of gates for the given inputs \( A \) and \( B \) shown in the figure. 
 

• A.
• B.
• C.
• D.

Hint:

De-Morgan’s Theorem is a useful tool to simplify Boolean expressions: \( \overline{A \cdot B} = \overline{A} + \overline{B} \) and \( \overline{A + B} = \overline{A} \cdot \overline{B} \).

Answer 1

The Correct Option is D

Step 1: {Understanding the Logic Circuit} 
The given circuit consists of: - NOT gates applied to inputs \( A \) and \( B \). - AND gate processing the inverted signals. 
Step 2: {Deriving the Boolean Expression} 
The circuit implements: \[ Y = \overline{A} \cdot \overline{B} \] Applying De-Morgan’s theorem: \[ Y = \overline{(A + B)} \] 
Step 3: {Comparing with Output Waveforms} 
Analyzing the truth table, we match the waveform and determine that the correct output is given by waveform 4. Thus, the correct answer is (D).