Identify the correct increasing order of energies of molecular orbitals for F 2 molecule.

Question

cdquestions Admin · Accepted Answer

Let's break down the options to understand why this is the correct order:

In the F₂ molecule, the $σ_{1s}$ bonding orbital is formed by the overlap of the two 1s atomic orbitals from each fluorine atom. This bonding orbital is lower in energy compared to the other molecular orbitals.
The $σ^{*}_{1s}$ antibonding orbital is formed by the destructive overlap of the two 1s atomic orbitals. It is higher in energy than the $σ_{1s}$ bonding orbital.
The $σ_{2s}$ bonding orbital is formed by the overlap of the two 2s atomic orbitals from each fluorine atom. It is lower in energy than the σ* 1s orbital.
Finally, the $σ^{*}_{2s}$ antibonding orbital is formed by the destructive overlap of the two 2s atomic orbitals. It is higher in energy than the $σ_{2s}$ bonding orbital.

Therefore, the correct order is $σ^{*}_{1s} < σ_{1s} < σ^{*}_{2s} < σ_{2s}$, which corresponds to option (D).

Answer

$σ_{1s}< σ^{*}_{1s} < σ_{2s} < σ^{*}_{2s}$

Answer

$σ_{1s}< σ_{2s} <σ^{*}_{1s} < σ^{*}_{2s}$

Answer

$σ_{1s} < σ^{*}_{1s} < σ^{*}_{2s} < σ_{2s}$

Answer

$σ ^{*}_{1s} < σ_{1s} < σ^{ *}_{2s} < σ_{2s}$

Identify the correct increasing order of energies of molecular orbitals for F₂ molecule.