Step 1: First-Order Reaction Integrated Rate Law The rate equation for a first-order reaction is: \[ \frac{d[A]}{dt} = - k[A] \] Upon integration, we obtain: \[ \ln [A] = \ln [A_0] - kt \] Or in terms of concentrations, \[ \log (a-x) = \log a - \frac{k}{2.303} t \]
Step 2: Interpretation of Graphs
- The equation shows that \(\log(a-x)\) vs. \( t \) gives a straight line with a negative slope.
- Option (4) correctly represents this linear decrease in the concentration of reactant \( A \) over time.
- Other options do not follow this logarithmic behavior.
Step 3: Conclusion
- The correct graphical representation for a first-order reaction is Option (4).
- The slope of the straight-line graph gives \(- k/2.303\), which can be used to determine the rate constant \( k \).
If \[ \int e^x (x^3 + x^2 - x + 4) \, dx = e^x f(x) + C, \] then \( f(1) \) is:
In Bohr model of hydrogen atom, if the difference between the radii of \( n^{th} \) and\( (n+1)^{th} \)orbits is equal to the radius of the \( (n-1)^{th} \) orbit, then the value of \( n \) is: