The reaction sequence provided involves the following steps:
- The starting compound is 1,2,2-tetrachloroethane (C$_2$H$_2$Cl$_4$). In the first step, this undergoes a reduction reaction with Zn at elevated temperature, which typically leads to the replacement of the halogen atoms by hydrogen atoms, forming an intermediate compound (A).
- In the second step, the intermediate undergoes nitration using con(C) HNO$_3$, which introduces a NO$_2$ group into the benzene ring, resulting in compound (B).
- The third step involves chlorination with con(C) H$_2$SO$_4$, leading to the formation of a chloro derivative, (C).
- The final step is an alkylation with anhydrous AlCl$_3$, which leads to the formation of compound (D).
The correct option corresponding to this sequence is (C)
Thus, the compounds identified in this sequence are as follows:
- A: C$_6$H$_5$CH$_3$
- B: C$_6$H$_5$NO$_2$
- C: C$_6$H$_4$Cl
- D: C$_6$H$_4$ClNO$_2$