Question:

Identify product A in the following reaction: 
\(\text{C}_6\text{H}_5\text{C(O)}\text{NH}_2 + \text{H}_2\text{O} + \text{HCl} \rightarrow A \)
 

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Hydrolysis of an amide in the presence of water and an acid produces a carboxylic acid and ammonia.
Updated On: Jan 26, 2026
  • C$_6$H$_5$C(O)OH
  • C$_6$H$_5$C(NH$_2$)
  • C$_6$H$_5$C(Cl)
  • C$_6$H$_5$C(H)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the reaction.
The reaction involves the hydrolysis of an amide (C$_6$H$_5$C(O)NH$_2$) in the presence of water and hydrochloric acid. Hydrolysis of amides produces a carboxylic acid and ammonia.
Step 2: Analyzing the options.
(A) C$_6$H$_5$C(O)OH: This is the correct product. Hydrolysis of the amide group results in the formation of a carboxylic acid, phenyl acetic acid (C$_6$H$_5$C(O)OH).
(B) C$_6$H$_5$C(NH$_2$): This is incorrect, as it represents an amine group, which is not formed in this reaction.
(C) C$_6$H$_5$C(Cl): This is incorrect, as no chlorination is involved in this reaction.
(D) C$_6$H$_5$C(H): This is incorrect, as no reduction to an aldehyde is involved.
Step 3: Conclusion.
The correct product is (A) C$_6$H$_5$C(O)OH, phenyl acetic acid.
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