In this problem, we need to identify the products formed in two different conditions of chlorination of benzene:
\(\text{hv}\ (\text{light})\) condition leading to Product A
\(\text{CCl}_4\) (in the presence of a solvent) condition leading to Product B
Step-by-step Explanation:
In the presence of \(\text{hv}\ (\text{light})\) (Product A):
When benzene reacts with chlorine under UV light, a substitution reaction occurs where a hydrogen atom is replaced by a chlorine atom.
This process leads to the formation of chlorobenzene.
In the presence of carbon tetrachloride \(\text{(CCl}_4\text{)}\)(Product B):
Chlorination in the presence of \(\text{CCl}_4\) typically involves a side-chain chlorination of any alkyl group attached to the benzene ring. However, as pure benzene doesn’t have such a group, it's also likely that the context meant chlorobenzene formation or no reaction (commonly happens when the conditions or context is misread for pure benzene reactions).
Conclusion:
Product A is Chlorobenzene (as formed under light).
Product B could typically again be interpreted in similar chlorobenzene contexts depending on exam setup. For this specific pattern, they could trick into redundant options or more detailed benzene derivatives' experimental setups.
Thus, matching interpretations logically, the correct answer identified previously in similar isinstance awareness setups would be
Answer: Product interpretation (semi-historically) over competition settings lands on priorities guided through similar exam situation setups.
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Approach Solution -2
In this reaction:
- Product A is formed through a free radical mechanism. - Product B is formed through an electrophilic addition reaction on the alkene.
The correct answer is option (4), where Product A is formed by the free radical mechanism and Product B is formed by electrophilic addition in the presence of CCl4.
