Question

Identify 'B' in the following series of reactions:
Ethanol $\xrightarrow{\text{NaBr, H\(_2\)SO\(_4\), Δ}}$ A $\xrightarrow{\text{Mg, Dry ether}}$ B

• A. Ethyl magnesium bromide
• B. Ethyl bromide
• C. Sodium ethoxide
• D. Ethene

Hint:

The reaction of alkyl halides with magnesium in dry ether produces Grignard reagents like ethyl magnesium bromide.

Answer 1

The Correct Option is A

Step 1: Analyzing the reaction.
- The first reaction involves the reaction of ethanol with sodium bromide (NaBr) and sulfuric acid (H\(_2\)SO\(_4\)), resulting in the formation of ethyl bromide (C\(_2\)H\(_5\)Br). - The second reaction involves the reaction of ethyl bromide with magnesium (Mg) in dry ether, forming ethyl magnesium bromide (C\(_2\)H\(_5\)MgBr). This is a Grignard reagent.

Step 2: Analyzing the options.
(A) Ethyl magnesium bromide: Correct — This is the product formed in the second reaction when ethyl bromide reacts with magnesium in dry ether.
(B) Ethyl bromide: This is the intermediate product from the first reaction, not the final product.
(C) Sodium ethoxide: Sodium ethoxide is not formed in this sequence of reactions.
(D) Ethene: Ethene is not produced in this sequence.

Step 3: Conclusion.
The correct answer is (A) Ethyl magnesium bromide.