Conversion of Ethanol to Ethyl Bromide (A): Ethanol reacts with bromine in the presence of red phosphorus to form ethyl bromide. \[ CH_3CH_2OH + Br_2 \xrightarrow{\text{red P}} CH_3CH_2Br + HBr \] So, \( A = \) Ethyl Bromide \( (CH_3CH_2Br) \).
Conversion of Ethyl Bromide to Propanenitrile (B): Ethyl bromide reacts with alcoholic potassium cyanide \( (KCN) \) to form propanenitrile. \[ CH_3CH_2Br + KCN \rightarrow CH_3CH_2CN + KBr \] So, \( B = \) Propanenitrile \( (CH_3CH_2CN) \).
Conversion of Propanenitrile to Propylamine (C): Propanenitrile undergoes reduction with lithium aluminum hydride \( (LiAlH_4) \) in ether to form propylamine. \[ CH_3CH_2CN + 4[H] \xrightarrow{\text{LiAlH}_4, \text{Ether}} CH_3CH_2CH_2NH_2 \] So, \( C = \) Propylamine \( (CH_3CH_2CH_2NH_2) \).
Identify A in the following reaction. 
For the reaction, \(N_{2}O_{4} \rightleftharpoons 2NO_{2}\) graph is plotted as shown below. Identify correct statements.
A. Standard free energy change for the reaction is 5.40 kJ \(mol^{-1}\).
B. As \(\Delta G\) in graph is positive, \(N_{2}O_{4}\) will not dissociate into \(NO_{2}\) at all.
C. Reverse reaction will go to completion.
D. When 1 mole of \(N_{2}O_{4}\) changes into equilibrium mixture, value of \(\Delta G = -0.84 \text{ kJ mol}^{-1}\).
E. When 2 mole of \(NO_{2}\) changes into equilibrium mixture, \(\Delta G\) for equilibrium mixture is \(-6.24 \text{ kJ mol}^{-1}\).
Choose the correct answer from the following.
