Step 1: Elimination Reaction with Alcoholic KOH
When 1-bromopropane (CH3CH2CH2Br) is heated with alcoholic KOH, it undergoes β-elimination to form propene (CH3CH=CH2).
Reaction:
CH3CH2CH2Br + alc. KOH → CH3CH=CH2 + H2O + KBr
So, A is: CH3CH=CH2 (Propene)
Step 2: Electrophilic Addition with Br2
Propene reacts with bromine to give 1,2-dibromopropane.
Reaction:
CH3CH=CH2 + Br2 → CH3CHBrCH2Br
So, B is: CH3CHBrCH2Br (1,2-Dibromopropane)
Final Answer:
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is