Step 1: Elimination Reaction with Alcoholic KOH
When 1-bromopropane (CH3CH2CH2Br) is heated with alcoholic KOH, it undergoes β-elimination to form propene (CH3CH=CH2).
Reaction:
CH3CH2CH2Br + alc. KOH → CH3CH=CH2 + H2O + KBr
So, A is: CH3CH=CH2 (Propene)
Step 2: Electrophilic Addition with Br2
Propene reacts with bromine to give 1,2-dibromopropane.
Reaction:
CH3CH=CH2 + Br2 → CH3CHBrCH2Br
So, B is: CH3CHBrCH2Br (1,2-Dibromopropane)
Final Answer:
Read the following statements: Statement I: All vertebrates develop a row of vestigial gill slits during embryonic stage.
Statement II: Embryos always pass through the adult stages of other animals.