Step 1: Elimination Reaction with Alcoholic KOH
When 1-bromopropane (CH3CH2CH2Br) is heated with alcoholic KOH, it undergoes β-elimination to form propene (CH3CH=CH2).
Reaction:
CH3CH2CH2Br + alc. KOH → CH3CH=CH2 + H2O + KBr
So, A is: CH3CH=CH2 (Propene)
Step 2: Electrophilic Addition with Br2
Propene reacts with bromine to give 1,2-dibromopropane.
Reaction:
CH3CH=CH2 + Br2 → CH3CHBrCH2Br
So, B is: CH3CHBrCH2Br (1,2-Dibromopropane)
Final Answer:
You are given a dipole of charge \( +q \) and \( -q \) separated by a distance \( 2l \). A sphere 'A' of radius \( R \) passes through the centre of the dipole as shown below and another sphere 'B' of radius \( 2R \) passes through the charge \( +q \). Then the electric flux through the sphere A is