Question:
\(I(x)=\int\frac{6dx}{sin^2x(1+\cot x)^2}\)and I(0) then I (\(\frac{\pi}{2}\)) is equal to
\(I(x)=\int\frac{6dx}{sin^2x(1+\cot x)^2}\)and I(0) then I (\(\frac{\pi}{2}\)) is equal to
Updated On: Nov 8, 2024
- \(\frac{21-9\sqrt{3}}{3-\sqrt{3}}\)
- \(\frac{21+9\sqrt{3}}{3-\sqrt{3}}\)
- \(\frac{21}{3-\sqrt{3}}\)
- \(\frac{3+\sqrt{3}}{3-\sqrt{3}}\)
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The Correct Option is A
Solution and Explanation
The Correct answer is option is (A) : \(\frac{21-9\sqrt{3}}{3-\sqrt{3}}\)
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