Question

Hydrolysis products of isobutyl isonitrile are:

• A. (CH$_3$)$_2$CHCH$_2$NH$_2$ + HCOOH
• B. CH$_3$CH$_2$CH(CH$_3$)NH$_2$ + HCOOH
• C. (CH$_3$)$_2$CHNH$_2$ + CH$_3$COOH
• D. (CH$_3$)$_2$CHCOOH + CH$_3$NH$_2$

Hint:

Isocyanides (R–NC) hydrolyze in acid to give primary amine (R–NH$_2$) and formic acid (HCOOH).

Answer 1

The Correct Option is A

Isobutyl isonitrile is an isocyanide (R–NC). On hydrolysis under acidic conditions, isocyanides form a primary amine and formic acid. In this case, the isobutyl group is (CH$_3$)$_2$CHCH$_2$–. Hence, hydrolysis yields isobutylamine ((CH$_3$)$_2$CHCH$_2$NH$_2$) and formic acid (HCOOH). \[ \text{R–NC} + 2H_2O \rightarrow \text{R–NH}_2 + \text{HCOOH} \]

Answer 2

To find the hydrolysis products of isobutyl isonitrile:

Step 1: Identify the structure of isobutyl isonitrile.
Isobutyl group: \( (CH_3)_2CHCH_2- \)
Isonitrile group: \( -NC \) (also called isocyanide)
So, isobutyl isonitrile is: \( (CH_3)_2CHCH_2NC \)

Step 2: Understand the hydrolysis of isonitriles.
When an isonitrile (R-NC) undergoes hydrolysis in acidic medium, it yields a primary amine (R-NH₂) and formic acid (HCOOH).

Step 3: Apply this to isobutyl isonitrile.
R = \( (CH_3)_2CHCH_2 \)
So the products are:
- \( (CH_3)_2CHCH_2NH_2 \) (isobutylamine)
- \( HCOOH \) (formic acid)

Therefore, the hydrolysis products of isobutyl isonitrile are:
\[ \boxed{(CH_3)_2CHCH_2NH_2 + HCOOH} \]