Hybridisation and geometry of [Ni(CN)$_4$]$^{2-$ are:}
Show Hint
- sp$^3$ and tetrahedral
- sp$^3$ and square planar
- sp$^3$ and tetrahedral
- dsp$^2$ and square planar
The Correct Option is D
Solution and Explanation
Nickel in [Ni(CN)$_4$]$^{2-}$ has an oxidation state of \( +2 \).
Its electronic configuration: \( 3d^8 4s^0 \).
Step 2: Effect of Ligand
CN$^-$ is a strong field ligand, which causes pairing of electrons in the \( d \)-orbitals.
This leads to dsp$^2$ hybridization, forming a square planar geometry.
Final Answer: [Ni(CN)$_4$]$^{2-}$ undergoes dsp$^2$ hybridization, leading to a square planar shape.
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