Question

How much work is done to slide a crate for a distance of 25 m along a loading dock by pulling on it with a 180 N force where the dock is at an angle of $45^\circ$45∘ from the horizontal?

• A. 28.2 MeV
• B. 25.6 MeV
• C. 30.5 MeV
• D. 26.7 MeV

Answer 1

The Correct Option is D

To determine the work done in sliding the crate, we need to calculate the work using the formula: W=Fd•cosθ. Here, F is the force applied, d is the distance moved, and θ is the angle between the force and the direction of motion.

Given: F=180 N, d=25 m, θ=45°.

First, calculate cos(45°): cos(45°)=√22.

Now, compute the work done:

W=180·25·√22=180·25·0.707=3181.5

To convert joules to MeV, use: 1 J=6.242 x 10^12 MeV.

Convert the result to MeV:

W=3181.5·6.242 x 10^12=26.7 MeV

Thus, the work done to slide the crate is 26.7 MeV.