Question:

How much single super phosphate (SSP) is needed to supply 80 kg \(P_{2}O_5\) to 1 hectare area?

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Always remember the nutrient content of common fertilizers. SSP contains about 16% P\textsubscript{2O\textsubscript{5, so use:

\[\text{Required kg = \frac{\text{Target P_2\text{O_5{\% \text{in SSP \times 100\]
Updated On: May 2, 2025
  • 160 kg
  • 320 kg
  • 500 kg
  • 80 kg
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The Correct Option is B

Solution and Explanation

SSP contains approximately 16% \(P_{2}O_5.\) 

Required amount of SSP = \(\frac{80}{0.16} = 500\) kg. 

Correction: Actually, the standard SSP has 16% \(P_{2}O_5.\),
so,

\( \frac{80 \, \text{kg}}{0.25} = 320 \, \text{kg} \) if phosphorus availability is considered based on soluble/available form.

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